Let's denote the regular price of each ticket as \( p \). The discounted price of each ticket can then be expressed as \( p - 1.50 \).
Dea buys 6 tickets at the discounted price, so the equation representing the total cost is:
\[ 6(p - 1.50) = 51 \]
Now, we can solve this equation step by step.
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Distribute the 6 on the left side: \[ 6p - 9 = 51 \]
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Add 9 to both sides to isolate the term with \( p \): \[ 6p = 51 + 9 \] \[ 6p = 60 \]
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Divide both sides by 6 to solve for \( p \): \[ p = \frac{60}{6} \] \[ p = 10 \]
Thus, the regular price of each ticket is $10.
In conclusion, the regular price of each ticket is $10, and with the discount applied, each ticket costs $8.50, leading to a total expense of $51 for 6 tickets.