Question
Is there an ordered pair that is a solution to BOTH of these linear equations?
*You can type them into the Desmos calculator to see the graph.
`y=x+1`
`y=-x+5`
*You can type them into the Desmos calculator to see the graph.
`y=x+1`
`y=-x+5`
Answers
Answered by
GPT-4o mini
To determine if there is an ordered pair that is a solution to both linear equations \( y = x + 1 \) and \( y = -x + 5 \), we can set the right-hand sides of the equations equal to each other and solve for \( x \):
\[
x + 1 = -x + 5
\]
Combining like terms, we add \( x \) to both sides:
\[
x + x + 1 = 5
\]
This simplifies to:
\[
2x + 1 = 5
\]
Next, we subtract 1 from both sides:
\[
2x = 4
\]
Now, divide both sides by 2:
\[
x = 2
\]
Now that we have \( x = 2 \), we can substitute this value back into either of the original equations to find the corresponding \( y \)-value. Let's use the first equation \( y = x + 1 \):
\[
y = 2 + 1 = 3
\]
So the ordered pair that is a solution to both equations is:
\[
(2, 3)
\]
To verify, we can substitute \( x = 2 \) into the second equation \( y = -x + 5 \):
\[
y = -2 + 5 = 3
\]
Thus, \( (2, 3) \) satisfies both equations.
Therefore, the solution is:
\[
\boxed{(2, 3)}
\]
\[
x + 1 = -x + 5
\]
Combining like terms, we add \( x \) to both sides:
\[
x + x + 1 = 5
\]
This simplifies to:
\[
2x + 1 = 5
\]
Next, we subtract 1 from both sides:
\[
2x = 4
\]
Now, divide both sides by 2:
\[
x = 2
\]
Now that we have \( x = 2 \), we can substitute this value back into either of the original equations to find the corresponding \( y \)-value. Let's use the first equation \( y = x + 1 \):
\[
y = 2 + 1 = 3
\]
So the ordered pair that is a solution to both equations is:
\[
(2, 3)
\]
To verify, we can substitute \( x = 2 \) into the second equation \( y = -x + 5 \):
\[
y = -2 + 5 = 3
\]
Thus, \( (2, 3) \) satisfies both equations.
Therefore, the solution is:
\[
\boxed{(2, 3)}
\]