What is the volume of a cone with a radius of 5 inches and a height of 9 inches

1 answer

The volume \( V \) of a cone can be calculated using the formula:

\[ V = \frac{1}{3} \pi r^2 h \]

where \( r \) is the radius and \( h \) is the height of the cone.

Given:

  • Radius \( r = 5 \) inches
  • Height \( h = 9 \) inches

Now, substitute the values into the formula:

\[ V = \frac{1}{3} \pi (5)^2 (9) \]

Calculating \( (5)^2 \):

\[ (5)^2 = 25 \]

Now, multiply this by the height:

\[ 25 \times 9 = 225 \]

Now, substitute back into the formula:

\[ V = \frac{1}{3} \pi (225) \]

Now divide by 3:

\[ V = 75\pi \]

To get a numerical approximation, we can use \( \pi \approx 3.14 \):

\[ V \approx 75 \times 3.14 \approx 235.5 \]

Thus, the volume of the cone is approximately \( 235.5 \) cubic inches, or exactly \( 75\pi \) cubic inches.