Asked by Sienna
the molar heat of vaporization for water is 40.79 kJ/mol. How would you express this heat of vaporization in joules per gram.
Answers
Answered by
drwls
40,790 J/mole divide by 18 g/mole
= 2266 J/g
= 542 calories/g
= 2266 J/g
= 542 calories/g
Answer
40.79kj/mol =j/g
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