To compare the initial values of both linear functions, we need to identify what those initial values are.
Linear Function 1:
- Lionel’s cell phone plan costs $45 per month.
- This implies that the cost starts at $45 when \( x = 0 \), which means the initial value is $45.
Linear Function 2:
- The relationship is given by the equation \( y = 40x + 60 \).
- Here, when \( x = 0 \), \( y = 40(0) + 60 = 60 \). This means the initial value is $60.
Now we can compare the initial values:
- Linear Function 1 has an initial value of $45.
- Linear Function 2 has an initial value of $60.
Since \( 45 < 60 \), we conclude that:
Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.
So, the correct response is: Linear Function 1 has the lesser initial value, with an initial value equal to $45 while Linear Function 2 has an initial value equal to $60.