Asked by joshua
A snail climbs a wall that is 16 feet high. Each day the snail climbs 5 feet, but each night it slips back down 3 feet. How many days will it take for the snail to get to the top of the wall
Answers
Answered by
maddie
it will take 8 days for the snail to reach the top.
5-3+5-3+5-3+5-3+5-3+5-3+5-3+5-3= 16
5-3+5-3+5-3+5-3+5-3+5-3+5-3+5-3= 16
Answered by
MathMate
Day 1: 0+5=5
Night 1: 5-3=2
Day 2: 2+5=7
Night 2: 7-3=4
Day 3: 4+5=9
Night 3: 9-3=6
Day 4: 6+5=11
Night 4: 11-3=8
Day 5: 8+5=13
Night 5: 13-3=10
Day 6: 10+5=15
Night 6: 15-3=12
Day 7: 12+5=17
The snail is now out of the well.
Night 1: 5-3=2
Day 2: 2+5=7
Night 2: 7-3=4
Day 3: 4+5=9
Night 3: 9-3=6
Day 4: 6+5=11
Night 4: 11-3=8
Day 5: 8+5=13
Night 5: 13-3=10
Day 6: 10+5=15
Night 6: 15-3=12
Day 7: 12+5=17
The snail is now out of the well.
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