Find the value of the function y=3x2−21 when x=4 (1 point)

Question

y=

.

Answer 1

To find the value of the function \( y = 3x^2 - 21 \) when \( x = 4 \), plug in \( 4 \) for \( x \):

\[ y = 3(4)^2 - 21 \]

Calculate \( (4)^2 \):

\[ (4)^2 = 16 \]

Now, substitute this value back into the equation:

\[ y = 3(16) - 21 \]

Now, multiply \( 3 \) by \( 16 \):

\[ y = 48 - 21 \]

Finally, subtract \( 21 \) from \( 48 \):

\[ y = 27 \]

Therefore, the value of the function when \( x = 4 \) is \( \boxed{27} \).