For this question, please select the best answer for the molar mass of tin(II) bromide, SnBr2

You can use the interactive periodic table or your work above to solve this. (1 point)
Responses

278.5 g/mol
278.5 g/mol

118.7 g/mol
118.7 g/mol

159.8 g/mol
159.8 g/mol

317.3 g/mol

1 answer

To calculate the molar mass of tin(II) bromide (SnBr₂), you need to sum the molar masses of tin (Sn) and bromine (Br).

  • The molar mass of tin (Sn) is approximately 118.7 g/mol.
  • The molar mass of bromine (Br) is approximately 79.9 g/mol.

Since there are two bromine atoms in SnBr₂, you calculate the total for bromine:

\[ 2 \times 79.9 , \text{g/mol} = 159.8 , \text{g/mol} \]

Now, add the molar mass of tin:

\[ 118.7 , \text{g/mol} , (\text{Sn}) + 159.8 , \text{g/mol} , (\text{Br}) = 278.5 , \text{g/mol} \]

So, the molar mass of tin(II) bromide (SnBr₂) is 278.5 g/mol.

Therefore, the best answer is:

278.5 g/mol.

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