To calculate the molar mass of tin(II) bromide (SnBr₂), you need to sum the molar masses of tin (Sn) and bromine (Br).
- The molar mass of tin (Sn) is approximately 118.7 g/mol.
- The molar mass of bromine (Br) is approximately 79.9 g/mol.
Since there are two bromine atoms in SnBr₂, you calculate the total for bromine:
\[ 2 \times 79.9 , \text{g/mol} = 159.8 , \text{g/mol} \]
Now, add the molar mass of tin:
\[ 118.7 , \text{g/mol} , (\text{Sn}) + 159.8 , \text{g/mol} , (\text{Br}) = 278.5 , \text{g/mol} \]
So, the molar mass of tin(II) bromide (SnBr₂) is 278.5 g/mol.
Therefore, the best answer is:
278.5 g/mol.