Question
What is a 1/3lb 10 count at the cost of 6.75 /lb
Answers
GPT-4o mini
To calculate the cost of a 1/3 lb (which is approximately 0.333 lb) at a price of $6.75 per pound, you can use the following formula:
\[
\text{Cost} = \text{Weight} \times \text{Price per pound}
\]
Substituting the values:
\[
\text{Cost} = \frac{1}{3} \text{ lb} \times 6.75 \text{ /lb}
\]
\[
\text{Cost} = 0.333 \times 6.75 \approx 2.25
\]
So, the cost of a 1/3 lb item at $6.75 per pound is approximately **$2.25**.
If you need to calculate the cost for 10 counts (assuming each item is 1/3 lb), you would multiply by 10:
\[
\text{Total Cost} = 10 \times 2.25 = 22.50
\]
Thus, for 10 counts of 1/3 lb each at that cost, it would be **$22.50**.
\[
\text{Cost} = \text{Weight} \times \text{Price per pound}
\]
Substituting the values:
\[
\text{Cost} = \frac{1}{3} \text{ lb} \times 6.75 \text{ /lb}
\]
\[
\text{Cost} = 0.333 \times 6.75 \approx 2.25
\]
So, the cost of a 1/3 lb item at $6.75 per pound is approximately **$2.25**.
If you need to calculate the cost for 10 counts (assuming each item is 1/3 lb), you would multiply by 10:
\[
\text{Total Cost} = 10 \times 2.25 = 22.50
\]
Thus, for 10 counts of 1/3 lb each at that cost, it would be **$22.50**.