Asked by Keith
solve following using "elimination method"
3x^2 + 4y = 17
2x^2 + 5y = 12
3x^2 + 4y = 17
2x^2 + 5y = 12
Answers
Answered by
drwls
Multiply the first equation by 2 and the second equation by 3, and subtract one from the other. That will eliminate the x^2 variable.
6x^2 + 8y = 34
6x^2 + 15y = 36
7 y = 2
y = 2/7
2x^2 = 12 - 5y = 12 - 10/7
= 74/7
x = sqrt(37/7) = 2.299
6x^2 + 8y = 34
6x^2 + 15y = 36
7 y = 2
y = 2/7
2x^2 = 12 - 5y = 12 - 10/7
= 74/7
x = sqrt(37/7) = 2.299
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