To determine the probability of obtaining a tall, homozygous pea plant from a cross between two tall, heterozygous pea plants, let's first define the genotypes:
- Tall (dominant): T
- Short (recessive): t
Since both parent plants are heterozygous tall, their genotypes can be represented as Tt.
Now, we can set up a Punnett square:
T | t
----------------
T | TT | Tt
----------------
t | Tt | tt
From the Punnett square, we can see the possible genotypes of the offspring:
- TT (homozygous tall) = 1
- Tt (heterozygous tall) = 2
- tt (homozygous short) = 1
Now, let's summarize the results:
- TT: 1 (25%)
- Tt: 2 (50%)
- tt: 1 (25%)
To answer the question specifically about the probability of getting a tall, homozygous pea plant (TT), we see there is 1 out of 4 squares representing TT.
Thus, the probability that the offspring is a tall, homozygous pea plant is 25%.
The answer is a. 25%.