To solve the problem, let's analyze the scenario systematically.
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Initial Position:
- Lex tosses the water bottle from 5.5 feet above the ground. Therefore, the initial position of the water bottle is (0, 5.5).
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Using the Function:
- The height function of the water bottle is given by \( h(t) = -16t^2 + 32t + 5.5 \), where \( t \) is the time in seconds.
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Finding the Maximum Height:
- To find the maximum height, we need to determine the vertex of the parabola described by the height function. The formula for the vertex \( t \) coordinate is \( t = -\frac{b}{2a} \), where \( a = -16 \) and \( b = 32 \).
- Compute \( t \): \[ t = -\frac{32}{2 \times -16} = \frac{32}{32} = 1 \]
- Now substitute \( t = 1 \) back into the original height function to find the maximum height: \[ h(1) = -16(1)^2 + 32(1) + 5.5 = -16 + 32 + 5.5 = 21.5 \]
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Conclusion:
- The maximum height the water bottle can reach is 21.5 feet.
- Since Sara is 20 feet above the ground and the maximum height of the bottle (21.5 feet) is greater than 20 feet, Sara will be able to reach the bottle.
Thus, the correct response is: The initial position of the water bottle is (0, 5.5). The vertex of the throw is (1, 21.5). The maximum height the water bottle can reach is 21.5 feet. Sara will be able to reach the bottle.