Question
The magnetic field 0.02 m from a wire is 0.1 T. What is the magnitude of the magnetic field 0.01 m from the same wire?
0.01 T
0.05 T
0.1 T
0.2 T
0.01 T
0.05 T
0.1 T
0.2 T
Answers
GPT-4o mini
The magnetic field around a long straight wire carrying an electric current can be calculated using Ampère's Law. The magnitude of the magnetic field (B) at a distance (r) from the wire is given by the formula:
\[
B = \frac{\mu_0 I}{2 \pi r}
\]
where \( \mu_0 \) is the permeability of free space and \( I \) is the current through the wire.
From the formula, you can see that the magnetic field is inversely proportional to the distance from the wire. This means:
\[
B_1 r_1 = B_2 r_2
\]
Given:
- At \( r_1 = 0.02 \) m, \( B_1 = 0.1 \) T.
- We want to find \( B_2 \) at \( r_2 = 0.01 \) m.
Using the ratio:
\[
B_1 r_1 = B_2 r_2
\]
Substituting the known values:
\[
0.1 \times 0.02 = B_2 \times 0.01
\]
\[
0.002 = B_2 \times 0.01
\]
Now, solve for \( B_2 \):
\[
B_2 = \frac{0.002}{0.01}
\]
\[
B_2 = 0.2 \text{ T}
\]
Thus, the magnitude of the magnetic field 0.01 m from the wire is **0.2 T**.
\[
B = \frac{\mu_0 I}{2 \pi r}
\]
where \( \mu_0 \) is the permeability of free space and \( I \) is the current through the wire.
From the formula, you can see that the magnetic field is inversely proportional to the distance from the wire. This means:
\[
B_1 r_1 = B_2 r_2
\]
Given:
- At \( r_1 = 0.02 \) m, \( B_1 = 0.1 \) T.
- We want to find \( B_2 \) at \( r_2 = 0.01 \) m.
Using the ratio:
\[
B_1 r_1 = B_2 r_2
\]
Substituting the known values:
\[
0.1 \times 0.02 = B_2 \times 0.01
\]
\[
0.002 = B_2 \times 0.01
\]
Now, solve for \( B_2 \):
\[
B_2 = \frac{0.002}{0.01}
\]
\[
B_2 = 0.2 \text{ T}
\]
Thus, the magnitude of the magnetic field 0.01 m from the wire is **0.2 T**.