what expression is equivalent to √x^-3 y^-7 z^2 if x, y, and z are positive real numbers

1 answer

To simplify the expression \(\sqrt{x^{-3} y^{-7} z^{2}}\), we can rewrite the square root in terms of the exponent:

\[ \sqrt{x^{-3} y^{-7} z^{2}} = (x^{-3} y^{-7} z^{2})^{1/2} \]

Now, we can apply the exponent to each factor separately:

\[ = x^{-3/2} y^{-7/2} z^{2/2} \]

This simplifies to:

\[ = x^{-3/2} y^{-7/2} z^{1} \]

To write it in a more standard form, we can express the negative exponents as fractions:

\[ = \frac{z}{x^{3/2} y^{7/2}} \]

Thus, the expression equivalent to \(\sqrt{x^{-3} y^{-7} z^{2}}\) is:

\[ \frac{z}{x^{3/2} y^{7/2}} \]

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