Question

A water tank in the shape of a cone has a diameter of 12 feet and height of 15 feet what volume of water in cubic feet can the tank hold use 3.14 for pi and round ur answer to the nearest tenth

Answer 1

To calculate the volume of a cone, you can use the formula:

\[
V = \frac{1}{3} \pi r^2 h
\]

where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cone,
- \( \pi \) is approximately 3.14.

Given that the diameter of the cone is 12 feet, the radius \( r \) is:

\[
r = \frac{diameter}{2} = \frac{12}{2} = 6 \text{ feet}
\]

The height \( h \) of the cone is given as 15 feet. Now we can substitute the values into the volume formula:

\[
V = \frac{1}{3} \times 3.14 \times (6)^2 \times 15
\]

Calculating \( (6)^2 \):

\[
(6)^2 = 36
\]

Now, substituting \( 36 \) back into the volume formula:

\[
V = \frac{1}{3} \times 3.14 \times 36 \times 15
\]

Calculating \( 36 \times 15 \):

\[
36 \times 15 = 540
\]

Now, substituting \( 540 \) back into the formula:

\[
V = \frac{1}{3} \times 3.14 \times 540
\]

Calculating \( 3.14 \times 540 \):

\[
3.14 \times 540 = 1695.6
\]

Now, divide \( 1695.6 \) by 3:

\[
V = \frac{1695.6}{3} = 565.2
\]

Finally, rounding \( 565.2 \) to the nearest tenth, we get:

\[
\text{Volume} \approx 565.2 \text{ cubic feet}
\]

So, the volume of water the tank can hold is **565.2 cubic feet**.