Multiply (5−10i)(−3+8i)

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1 answer

To multiply the complex numbers \( (5 - 10i)(-3 + 8i) \), we can use the distributive property (also known as the FOIL method for binomials):

\[ (5 - 10i)(-3 + 8i) = 5 \cdot -3 + 5 \cdot 8i - 10i \cdot -3 - 10i \cdot 8i \]

Now, we calculate each term:

  1. \( 5 \cdot -3 = -15 \)
  2. \( 5 \cdot 8i = 40i \)
  3. \( -10i \cdot -3 = 30i \)
  4. \( -10i \cdot 8i = -80i^2 \)

Since \( i^2 = -1 \), we replace \( -80i^2 \) with \( 80 \):

Combining all the terms together:

\[ -15 + 40i + 30i + 80 \]

Combine the real parts and the imaginary parts:

Real part: \( -15 + 80 = 65 \)

Imaginary part: \( 40i + 30i = 70i \)

Therefore, the result of the multiplication is:

\[ 65 + 70i \]