Electrons are ejected from a photoelectric cell with a maximum kinetic energy of 1.20 eV. If the incident light has a wavelength of 410nm, what is the work funtion?

Answer 1

e*(Phi) = h*c/(lambda) - (max K.E.)
= photon energy - (max electron energy)

Solve for the work function phi, in electron volts

h is Planck's constant

Answer 2

yes that is what i did..and the answer i got is 2.93 x 10^-19 .. but i think its wrong :S

Answer 3

Your answer is in Joules. The work function is always given in electron volts (or just "volts"). Divide your number by e, the electron charge, to get phi, the work function.

Answer 4

oh okay thank u =)