Asked by Marium
Electrons are ejected from a photoelectric cell with a maximum kinetic energy of 1.20 eV. If the incident light has a wavelength of 410nm, what is the work funtion?
Answers
Answered by
drwls
e*(Phi) = h*c/(lambda) - (max K.E.)
= photon energy - (max electron energy)
Solve for the work function phi, in electron volts
h is Planck's constant
= photon energy - (max electron energy)
Solve for the work function phi, in electron volts
h is Planck's constant
Answered by
Marium
yes that is what i did..and the answer i got is 2.93 x 10^-19 .. but i think its wrong :S
Answered by
drwls
Your answer is in Joules. The work function is always given in electron volts (or just "volts"). Divide your number by e, the electron charge, to get phi, the work function.
Answered by
Marium
oh okay thank u =)
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