Question

Jett scores 3(1/3) points in the first round of a game and 3(2/5)
points in the second round. How many total points does he score for both rounds?(1 point)
7(11/15)

6(11/15)

6(3/8)

1/15

Answer 1

To find the total points Jett scores in the two rounds, we need to add the points from each round together.

1. First round: \(3 \frac{1}{3}\)
- Convert \(3 \frac{1}{3}\) to an improper fraction:
\[
3 \frac{1}{3} = \frac{3 \times 3 + 1}{3} = \frac{9 + 1}{3} = \frac{10}{3}
\]

2. Second round: \(3 \frac{2}{5}\)
- Convert \(3 \frac{2}{5}\) to an improper fraction:
\[
3 \frac{2}{5} = \frac{3 \times 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5}
\]

3. Now, to add \(\frac{10}{3}\) and \(\frac{17}{5}\), we need a common denominator.
- The least common multiple of 3 and 5 is 15.

4. Convert each fraction:
- \(\frac{10}{3}\) to a denominator of 15:
\[
\frac{10}{3} = \frac{10 \times 5}{3 \times 5} = \frac{50}{15}
\]

- \(\frac{17}{5}\) to a denominator of 15:
\[
\frac{17}{5} = \frac{17 \times 3}{5 \times 3} = \frac{51}{15}
\]

5. Now, add the two fractions:
\[
\frac{50}{15} + \frac{51}{15} = \frac{50 + 51}{15} = \frac{101}{15}
\]

6. Convert \(\frac{101}{15}\) to a mixed number:
- \(101 ÷ 15\) equals 6 with a remainder of 11 (since \(15 \times 6 = 90\), and \(101 - 90 = 11\)).
- Therefore, it becomes:
\[
6 \frac{11}{15}
\]

So the total points Jett scores for both rounds is \(6 \frac{11}{15}\).

The answer is: **6(11/15)**.