the pyramid is dilated using a scale factor of 2, what would be the new volume? to vide the volume of a pyramid, use V = lwh/3

Length = 12ft
width = 6ft
height = 15 ft

1 answer

To find the new volume of the pyramid after it has been dilated with a scale factor of 2, we first need to find the original volume.

The volume \( V \) of a pyramid is given by the formula:

\[ V = \frac{l \times w \times h}{3} \]

where:

  • \( l \) is the length,
  • \( w \) is the width,
  • \( h \) is the height.

Step 1: Calculate the original volume

Given:

  • Length \( l = 12 , \text{ft} \)
  • Width \( w = 6 , \text{ft} \)
  • Height \( h = 15 , \text{ft} \)

Plugging these values into the formula:

\[ V = \frac{12 \times 6 \times 15}{3} \]

Calculate the product:

\[ 12 \times 6 = 72 \]

Then,

\[ 72 \times 15 = 1080 \]

Now, divide by 3:

\[ V = \frac{1080}{3} = 360 , \text{ft}^3 \]

Step 2: Calculate the new volume after dilation

When a three-dimensional shape is dilated by a scale factor \( k \), its volume is scaled by a factor of \( k^3 \). In this case, \( k = 2 \), so:

\[ \text{Scale factor for volume} = k^3 = 2^3 = 8 \]

Now, multiply the original volume by this scale factor:

\[ \text{New Volume} = 360 \times 8 = 2880 , \text{ft}^3 \]

Conclusion

After dilating the pyramid using a scale factor of 2, the new volume is:

\[ \boxed{2880 , \text{ft}^3} \]