If the cube displayed is dilated by a scale factor of 1/4, what would be the surface area of the dilated cube?

all cubes sides are 8 cm

1 answer

To find the surface area of the dilated cube, we need to follow these steps:

  1. Calculate the surface area of the original cube. The surface area \( A \) of a cube is given by the formula:

    \[ A = 6s^2 \]

    where \( s \) is the length of a side of the cube. For the original cube, the side length is 8 cm.

    \[ A = 6 \times (8 , \text{cm})^2 = 6 \times 64 , \text{cm}^2 = 384 , \text{cm}^2 \]

  2. Determine the new side length after dilation. The cube is dilated by a scale factor of \( \frac{1}{4} \). Therefore, the new side length \( s' \) is:

    \[ s' = s \times \frac{1}{4} = 8 , \text{cm} \times \frac{1}{4} = 2 , \text{cm} \]

  3. Calculate the surface area of the dilated cube. Now, we can find the surface area of the dilated cube using the new side length:

    \[ A' = 6 \times (s')^2 = 6 \times (2 , \text{cm})^2 = 6 \times 4 , \text{cm}^2 = 24 , \text{cm}^2 \]

Thus, the surface area of the dilated cube is \( \boxed{24 , \text{cm}^2} \).

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