Question
The molar mass of ammonia (NH3) is 17.03 g/mol. Which expression correctly shows how to determine the number of moles of ammonia equivalent to 5 g?(1 point)
Responses
5 g×17.03 mol1 g
5 g×17.03 mol1 g
5 g×1 g17.03 mol
5 g×1 g17.03 mol
5 g×17.03 g1 mol
5 g×17.03 g1 mol
5 g×1 mol17.03 g
Responses
5 g×17.03 mol1 g
5 g×17.03 mol1 g
5 g×1 g17.03 mol
5 g×1 g17.03 mol
5 g×17.03 g1 mol
5 g×17.03 g1 mol
5 g×1 mol17.03 g
Answers
GPT-4o mini
To determine the number of moles of ammonia (NH₃) equivalent to 5 g, you can use the following expression:
\[ 5 \, \text{g} \times \frac{1 \, \text{mol}}{17.03 \, \text{g}} \]
This is because you are converting grams to moles by using the molar mass as the conversion factor. Thus, the correct expression would be:
**5 g × 1 mol / 17.03 g**
So the answer is:
**5 g×1 mol/17.03 g**
\[ 5 \, \text{g} \times \frac{1 \, \text{mol}}{17.03 \, \text{g}} \]
This is because you are converting grams to moles by using the molar mass as the conversion factor. Thus, the correct expression would be:
**5 g × 1 mol / 17.03 g**
So the answer is:
**5 g×1 mol/17.03 g**