Question
Tomaz draws a circle and dilates it on a photocopier using a scale factor of 3. If the original circle has a radius of 3cm, what is the area of the dilated circle? Round your answer to the nearest tenth of a square centimeter.
The area of the dilated circle is approximately _ square centimeters
The area of the dilated circle is approximately _ square centimeters
Answers
GPT-4o mini
To find the area of the dilated circle, we start with the original circle which has a radius of 3 cm.
The area \( A \) of a circle is given by the formula:
\[
A = \pi r^2
\]
where \( r \) is the radius of the circle.
1. Calculate the area of the original circle:
\[
A_{\text{original}} = \pi (3 \, \text{cm})^2 = \pi \times 9 \, \text{cm}^2 = 9\pi \, \text{cm}^2
\]
2. Apply the scale factor of 3 to the radius of the circle:
\[
\text{New radius} = 3 \times 3 \, \text{cm} = 9 \, \text{cm}
\]
3. Calculate the area of the dilated circle using the new radius:
\[
A_{\text{dilated}} = \pi (9 \, \text{cm})^2 = \pi \times 81 \, \text{cm}^2 = 81\pi \, \text{cm}^2
\]
4. Now, we need to approximate the area in square centimeters. Using \( \pi \approx 3.14 \):
\[
A_{\text{dilated}} \approx 81 \times 3.14 = 254.34 \, \text{cm}^2
\]
5. Round the area:
\[
A_{\text{dilated}} \approx 254.3 \, \text{cm}^2
\]
Therefore, the area of the dilated circle is approximately **254.3 square centimeters**.
The area \( A \) of a circle is given by the formula:
\[
A = \pi r^2
\]
where \( r \) is the radius of the circle.
1. Calculate the area of the original circle:
\[
A_{\text{original}} = \pi (3 \, \text{cm})^2 = \pi \times 9 \, \text{cm}^2 = 9\pi \, \text{cm}^2
\]
2. Apply the scale factor of 3 to the radius of the circle:
\[
\text{New radius} = 3 \times 3 \, \text{cm} = 9 \, \text{cm}
\]
3. Calculate the area of the dilated circle using the new radius:
\[
A_{\text{dilated}} = \pi (9 \, \text{cm})^2 = \pi \times 81 \, \text{cm}^2 = 81\pi \, \text{cm}^2
\]
4. Now, we need to approximate the area in square centimeters. Using \( \pi \approx 3.14 \):
\[
A_{\text{dilated}} \approx 81 \times 3.14 = 254.34 \, \text{cm}^2
\]
5. Round the area:
\[
A_{\text{dilated}} \approx 254.3 \, \text{cm}^2
\]
Therefore, the area of the dilated circle is approximately **254.3 square centimeters**.