A trapezoid has a base of 10 inches, sides of 8 inches, and a top length of 4 inches. Suppose the trapezoid is dilated using a scale factor of 1/2. What is the perimeter of the dilated trapezoid?

1 answer

To find the perimeter of the dilated trapezoid, we first need to calculate the perimeter of the original trapezoid.

The original trapezoid has the following dimensions:

  • Base (bottom) = 10 inches
  • Top = 4 inches
  • Side 1 = 8 inches
  • Side 2 = 8 inches

Now we calculate the perimeter of the original trapezoid:

\[ \text{Perimeter} = \text{Base} + \text{Top} + \text{Side 1} + \text{Side 2} \]

Substituting the values:

\[ \text{Perimeter} = 10 + 4 + 8 + 8 = 30 \text{ inches} \]

Next, since the trapezoid is dilated using a scale factor of \( \frac{1}{2} \), we compute the perimeter of the dilated trapezoid. The perimeter of a figure is also scaled by the same factor when the figure undergoes dilation. Therefore, we multiply the original perimeter by \( \frac{1}{2} \):

\[ \text{Perimeter of dilated trapezoid} = \text{Original Perimeter} \times \frac{1}{2} = 30 \times \frac{1}{2} = 15 \text{ inches} \]

Thus, the perimeter of the dilated trapezoid is:

\[ \boxed{15 \text{ inches}} \]