Question

\(4.8^{2}+28.6^{2}=x^{2}\) round to the nearest tenth if necessary

Answer 1

To find \( x \) in the equation \( 4.8^2 + 28.6^2 = x^2 \), we first need to calculate \( 4.8^2 \) and \( 28.6^2 \).

1. Calculate \( 4.8^2 \):
\[
4.8^2 = 23.04
\]

2. Calculate \( 28.6^2 \):
\[
28.6^2 = 817.96
\]

3. Now, add both results:
\[
4.8^2 + 28.6^2 = 23.04 + 817.96 = 841.00
\]

4. Now, take the square root to solve for \( x \):
\[
x = \sqrt{841} = 29
\]

Thus, the value of \( x \) rounded to the nearest tenth is:
\[
\boxed{29.0}
\]