Sure! Here are some multi-step equation problems suitable for Grade 7, along with their solutions. You can use these for online practice.
Problems
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\( 3x + 5 = 20 \)
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\( 4(y - 2) = 16 \)
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\( 2(3z + 4) = 28 \)
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\( 5a - 7 = 3a + 9 \)
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\( 2(x + 3) - 4 = 10 \)
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\( 7 - 2b = 3b + 1 \)
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\( 6(c - 2) + 4 = 2(c + 6) \)
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\( \frac{2d}{3} - 5 = 9 \)
Solutions
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Solution to \( 3x + 5 = 20 \): \[ 3x = 20 - 5 \ 3x = 15 \ x = 5 \]
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Solution to \( 4(y - 2) = 16 \): \[ y - 2 = 4 \ y = 4 + 2 \ y = 6 \]
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Solution to \( 2(3z + 4) = 28 \): \[ 3z + 4 = 14 \ 3z = 14 - 4 \ 3z = 10 \ z = \frac{10}{3} \text{ or approximately } 3.33 \]
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Solution to \( 5a - 7 = 3a + 9 \): \[ 5a - 3a = 9 + 7 \ 2a = 16 \ a = 8 \]
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Solution to \( 2(x + 3) - 4 = 10 \): \[ 2x + 6 - 4 = 10 \ 2x + 2 = 10 \ 2x = 10 - 2 \ 2x = 8 \ x = 4 \]
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Solution to \( 7 - 2b = 3b + 1 \): \[ 7 - 1 = 3b + 2b \ 6 = 5b \ b = \frac{6}{5} \text{ or } 1.2 \]
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Solution to \( 6(c - 2) + 4 = 2(c + 6) \): \[ 6c - 12 + 4 = 2c + 12 \ 6c - 8 = 2c + 12 \ 6c - 2c = 12 + 8 \ 4c = 20 \ c = 5 \]
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Solution to \( \frac{2d}{3} - 5 = 9 \): \[ \frac{2d}{3} = 9 + 5 \ \frac{2d}{3} = 14 \ 2d = 42 \ d = 21 \]
Feel free to practice more with these problems, or create new ones! If you need any specific topics or types of problems, let me know!