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Question
Use the equation of motion to answer the question.

x=x0 +v0t + 12at2

An object has a starting position of X = 2 m, a starting velocity of 4.5 m/s, and no acceleration. Which option shows the final position of the object after 2 s?

(1 point)
Responses

18 m
18 m

11 m
11 m

9 m
9 m

5.5 m
5.5 m
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Answer 1

To find the final position of the object after 2 seconds, we can use the equation of motion:

\[ x = x_0 + v_0 t + \frac{1}{2} a t^2 \]

Given:
- Initial position \( x_0 = 2 \) m
- Initial velocity \( v_0 = 4.5 \) m/s
- Acceleration \( a = 0 \) m/s² (since there is no acceleration)
- Time \( t = 2 \) s

Substituting the values into the equation:

\[ x = 2 \, \text{m} + (4.5 \, \text{m/s} \times 2 \, \text{s}) + \frac{1}{2} (0 \, \text{m/s}^2) (2 \, \text{s})^2 \]

Calculating each term:

1. Initial position: \( 2 \, \text{m} \)
2. Velocity term: \( 4.5 \, \text{m/s} \times 2 \, \text{s} = 9 \, \text{m} \)
3. Acceleration term: since \( a = 0 \), the term is \( 0 \).

Now adding these together:

\[ x = 2 \, \text{m} + 9 \, \text{m} + 0 = 11 \, \text{m} \]

Therefore, the final position of the object after 2 seconds is **11 m**.