Question
Jim invested $1526
at %8
compounded continuously. How much will she have after 10 years?
Compound Interest Formula:
Answers
GPT-4o mini
To calculate the amount Jim will have after 10 years with continuous compounding, we can use the formula for continuously compounded interest:
\[
A = Pe^{rt}
\]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time the money is invested for in years.
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
In this case:
- \( P = 1526 \)
- \( r = 0.08 \) (which is 8% expressed as a decimal)
- \( t = 10 \)
Now we can substitute the values into the formula:
\[
A = 1526 \times e^{(0.08 \times 10)}
\]
Calculating the exponent:
\[
0.08 \times 10 = 0.8
\]
Now calculating \( e^{0.8} \):
\[
e^{0.8} \approx 2.22554 \text{ (using a calculator)}
\]
Now, substitute back into the formula:
\[
A = 1526 \times 2.22554 \approx 3395.54
\]
So, after 10 years, Jim will have approximately **$3395.54**.
\[
A = Pe^{rt}
\]
Where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (the initial amount of money).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time the money is invested for in years.
- \( e \) is the base of the natural logarithm (approximately equal to 2.71828).
In this case:
- \( P = 1526 \)
- \( r = 0.08 \) (which is 8% expressed as a decimal)
- \( t = 10 \)
Now we can substitute the values into the formula:
\[
A = 1526 \times e^{(0.08 \times 10)}
\]
Calculating the exponent:
\[
0.08 \times 10 = 0.8
\]
Now calculating \( e^{0.8} \):
\[
e^{0.8} \approx 2.22554 \text{ (using a calculator)}
\]
Now, substitute back into the formula:
\[
A = 1526 \times 2.22554 \approx 3395.54
\]
So, after 10 years, Jim will have approximately **$3395.54**.