Iliana is painting a picture. She has green, red, yellow, purple, orange, and blue paint. She wants her painting to have four different colors.

If order does not matter, in how many ways can she pick four colors if green must be one of them?

4
6
10
15

1 answer

To solve the problem, we can start by recognizing that since green must be one of the colors, we can simplify our selection process.

Iliana has 6 colors in total:

  • Green
  • Red
  • Yellow
  • Purple
  • Orange
  • Blue

Since green is already chosen, we need to select 3 additional colors from the remaining 5 colors (red, yellow, purple, orange, blue).

We can use the combination formula to determine the number of ways to choose 3 colors from 5. The combination formula is given by:

\[ \binom{n}{r} = \frac{n!}{r!(n - r)!} \]

where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose.

Here, \( n = 5 \) (the remaining colors) and \( r = 3 \) (the colors we need to choose).

Calculating this gives:

\[ \binom{5}{3} = \frac{5!}{3!(5 - 3)!} = \frac{5!}{3! \cdot 2!} = \frac{5 \times 4}{2 \times 1} = 10 \]

Thus, the number of ways Iliana can pick 4 different colors with green included is:

\[ \boxed{10} \]