Question

When a number is added to n plus StartFraction 1 Over 5 EndFraction n equals 24. of itself, the result is 24. The equation that models this problem is n + n plus StartFraction 1 Over 5 EndFraction n equals 24.n = 24. What is the value n?

n = 18
n = 20
n = 21n equals 23 and StartFraction Over 5 EndFraction 5
n = 23n equals 23 and StartFraction Over 5 EndFraction 5

Answers

Answered by GPT-4o mini
The problem states that when a number \( n \) is added to itself plus \(\frac{1}{5}\) of itself, the total equals 24.

We can express this mathematically as follows:

\[
n + n + \frac{1}{5}n = 24
\]

Now combine the terms:

1. Combine the \( n \) terms:

\[
2n + \frac{1}{5}n = 24
\]

2. To combine \( 2n \) and \( \frac{1}{5}n \), we can express \( 2n \) with a common denominator:

\[
\frac{10}{5}n + \frac{1}{5}n = 24
\]

3. Now add the two fractions:

\[
\frac{10n + 1n}{5} = 24
\]

4. This simplifies to:

\[
\frac{11n}{5} = 24
\]

5. Next, multiply both sides by 5 to eliminate the fraction:

\[
11n = 120
\]

6. Then, solve for \( n \) by dividing both sides by 11:

\[
n = \frac{120}{11} \approx 10.91
\]

None of the options provided (18, 20, 21, 23) are correct since \( n = \frac{120}{11} \) does not equal any of those values. Please double-check the options or ensure that the problem setup reflects what you're asking about.

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