What value is equivalent to log243 to the nearest thousandth? Use the change of base formula to determine your answer.(1 point) Responses 1.332 1.332 0.184 0.184 5.426 5.426 0.817

1 answer

To find the value of \(\log_{2} 43\) using the change of base formula, we can use the formula:

\[ \log_{b} a = \frac{\log_{c} a}{\log_{c} b} \]

We can use base 10 (or natural logarithm, base e) for our calculations. For this example, we'll use base 10.

Using the change of base formula:

\[ \log_{2} 43 = \frac{\log_{10} 43}{\log_{10} 2} \]

Now, we can calculate \(\log_{10} 43\) and \(\log_{10} 2\) using a calculator:

\[ \log_{10} 43 \approx 1.633 \] \[ \log_{10} 2 \approx 0.301 \]

Substituting these values into the change of base formula gives:

\[ \log_{2} 43 \approx \frac{1.633}{0.301} \approx 5.426 \]

Rounding to the nearest thousandth, we find:

\[ \log_{2} 43 \approx 5.426 \]

Thus, the value equivalent to \(\log_{2} 43\) rounded to the nearest thousandth is 5.426.