To find the slant height of the square pyramid, we can use the right triangle formed by the height of the pyramid, half of the base length, and the slant height.
- The height (h) of the pyramid is given as 15 feet.
- The length of the base (l) is 16 feet, therefore half of the base length (which is the base of the right triangle) is \( \frac{l}{2} = \frac{16}{2} = 8 \) feet.
Now, we can use the Pythagorean theorem to find the slant height \( s \):
\[ s^2 = h^2 + \left(\frac{l}{2}\right)^2 \] \[ s^2 = 15^2 + 8^2 \] \[ s^2 = 225 + 64 \] \[ s^2 = 289 \] \[ s = \sqrt{289} = 17 \text{ feet} \]
Thus, the slant height of the square pyramid is 17 feet.