Question 25

Question

An object moves a distance of 10 meters in 5 seconds. What is the average speed of the object?

a
40 m/s
b
50 m/s
c
2.0 m/s
d
0.5 m/s
Question 26
Look at the following equation.

Fe + Cl2 → FeCl3

In order to follow the law of conservation of mass, this equation must have which set of coefficients, in order from left to right?

Blank 1:
Blank 2:
Blank 3:

Answer 1

Question 25:

To calculate the average speed of the object, you can use the formula for average speed:

\[ \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} \]

Given:

• Total distance = 10 meters
• Total time = 5 seconds

Plugging in the values:

\[ \text{Average speed} = \frac{10 \text{ m}}{5 \text{ s}} = 2.0 \text{ m/s} \]

So the answer is: c) 2.0 m/s

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Question 26:

To balance the equation \( \text{Fe} + \text{Cl}_2 \rightarrow \text{FeCl}_3 \), we need to ensure the number of each atom on both sides is equal.

1. On the left side, there is 1 iron (Fe) atom.
2. On the left side, there are 2 chlorine (Cl) atoms from \(\text{Cl}_2\).
3. On the right side, there is 1 iron (Fe) atom and 3 chlorine (Cl) atoms in \(\text{FeCl}_3\).

To balance the chlorines, we can put a coefficient of 3 in front of \(\text{Fe}\) and a coefficient of 1 in front of \(\text{Cl}_2\):

\[ 3\text{Fe} + \text{Cl}_2 \rightarrow 2\text{FeCl}_3 \]

Now, we have:

• Left: 3 Fe and 2 Cl
• Right: 3 Fe and 6 Cl (from 2*3 in \(\text{FeCl}_3\))

Now we need to adjust the left side:

• Change the coefficient in front of \(\text{Cl}_2\) to 3:

\[ 3\text{Fe} + 3\text{Cl}_2 \rightarrow 2\text{FeCl}_3 \]

Now both sides have 3 Fe and 6 Cl atoms. So the balanced coefficients are:

Blank 1: 3 Blank 2: 3 Blank 3: 2

Final Coefficients:

• Blank 1: 3 (for Fe)
• Blank 2: 3 (for Cl2)
• Blank 3: 2 (for FeCl3)