Asked by dee
A pentagon with the a perimeter of 45 feet , what is the area
Answers
Answered by
Reiny
if it is a regular pentagon then each side is 9 feet.
We could draw 5 identical isosceles triangles with sides 9 and contained angle of 360/5° or 72°
Area of one of these = (1/2)(9)(9)sin72 = 38.517789
but we have 5 of them so
total area = 192.59 ft^2
We could draw 5 identical isosceles triangles with sides 9 and contained angle of 360/5° or 72°
Area of one of these = (1/2)(9)(9)sin72 = 38.517789
but we have 5 of them so
total area = 192.59 ft^2
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