A pentagon with the a perimeter of 45 feet , what is the area

Answer 1

if it is a regular pentagon then each side is 9 feet.

We could draw 5 identical isosceles triangles with sides 9 and contained angle of 360/5° or 72°

Area of one of these = (1/2)(9)(9)sin72 = 38.517789
but we have 5 of them so
total area = 192.59 ft^2