Question

Question 19
One molecule of Iodine (I2) and two molecules of sodium chloride (NaCl) combine in a reaction. How many atoms are in the products?

a
6
b
4
c
2
d
3

Answer 1

To determine the number of atoms in the products of the reaction between one molecule of Iodine (I2) and two molecules of sodium chloride (NaCl), we need to analyze the components involved:

1. One molecule of Iodine (I2) consists of 2 iodine atoms.
2. Two molecules of sodium chloride (NaCl) contain:
- Each molecule of NaCl consists of 1 sodium atom and 1 chlorine atom.
- Therefore, two molecules of NaCl contribute a total of:
- Sodium atoms: 2 Na
- Chlorine atoms: 2 Cl

Now, let's total the atoms from the reactants:
- From I2: 2 I (iodine atoms)
- From 2 NaCl: 2 Na (sodium atoms) + 2 Cl (chlorine atoms)

Now, summing these up:
- Total atoms = 2 I + 2 Na + 2 Cl = 6 atoms

So, the total number of atoms in the products is 6.

The correct answer is:
**a. 6**