Find the 19th term of the sequence described below, where n represents the position of a term in the sequence. an = 81n − 56 Submit

Answer 1

To find the 19th term of the sequence defined by $a_n=81n-56$, we need to substitute $n=19$ into the formula.

$$a_{19}=81(19)-56$$

Calculating $81\times 19$:

$$81\times 19=1539$$

Now substitute this value back into the equation:

$$a_{19}=1539-56$$

Now calculate $1539-56$:

$$1539-56=1483$$

Thus, the 19th term of the sequence is:

$$\boxed{{\displaystyle 1483}}$$