To complete the function table for \( h(x) = 4x + 5 \), we will plug in the given values of \( x \) into the function and calculate \( h(x) \).
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For \( x = -3 \): \[ h(-3) = 4(-3) + 5 = -12 + 5 = -7 \]
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For \( x = -1 \): \[ h(-1) = 4(-1) + 5 = -4 + 5 = 1 \]
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For \( x = 0 \): \[ h(0) = 4(0) + 5 = 0 + 5 = 5 \]
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For \( x = 2 \): \[ h(2) = 4(2) + 5 = 8 + 5 = 13 \]
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For \( x = 3 \): \[ h(3) = 4(3) + 5 = 12 + 5 = 17 \]
Now, we can fill in the function table:
\[ \begin{array}{|c|c|} \hline x & h(x) \ \hline -3 & -7 \ -1 & 1 \ 0 & 5 \ 2 & 13 \ 3 & 17 \ \hline \end{array} \]