Asked by Lee Hooni 🖤
The function h is defined by the following rule. h(x) = 4x+5 Complete the function table.
x h (x)
-3 _
-1 _
0 _
2 _
3 _
_ this symbol means there is an empty space
x h (x)
-3 _
-1 _
0 _
2 _
3 _
_ this symbol means there is an empty space
Answers
Answered by
Lee Hooni 🖤
whats the answer
Answered by
GPT-4o mini
To complete the function table for \( h(x) = 4x + 5 \), we will plug in the given values of \( x \) into the function and calculate \( h(x) \).
1. For \( x = -3 \):
\[
h(-3) = 4(-3) + 5 = -12 + 5 = -7
\]
2. For \( x = -1 \):
\[
h(-1) = 4(-1) + 5 = -4 + 5 = 1
\]
3. For \( x = 0 \):
\[
h(0) = 4(0) + 5 = 0 + 5 = 5
\]
4. For \( x = 2 \):
\[
h(2) = 4(2) + 5 = 8 + 5 = 13
\]
5. For \( x = 3 \):
\[
h(3) = 4(3) + 5 = 12 + 5 = 17
\]
Now, we can fill in the function table:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
-3 & -7 \\
-1 & 1 \\
0 & 5 \\
2 & 13 \\
3 & 17 \\
\hline
\end{array}
\]
1. For \( x = -3 \):
\[
h(-3) = 4(-3) + 5 = -12 + 5 = -7
\]
2. For \( x = -1 \):
\[
h(-1) = 4(-1) + 5 = -4 + 5 = 1
\]
3. For \( x = 0 \):
\[
h(0) = 4(0) + 5 = 0 + 5 = 5
\]
4. For \( x = 2 \):
\[
h(2) = 4(2) + 5 = 8 + 5 = 13
\]
5. For \( x = 3 \):
\[
h(3) = 4(3) + 5 = 12 + 5 = 17
\]
Now, we can fill in the function table:
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
-3 & -7 \\
-1 & 1 \\
0 & 5 \\
2 & 13 \\
3 & 17 \\
\hline
\end{array}
\]
Answered by
GPT-4o mini
Here is the completed function table for \( h(x) = 4x + 5 \):
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
-3 & -7 \\
-1 & 1 \\
0 & 5 \\
2 & 13 \\
3 & 17 \\
\hline
\end{array}
\]
So the values of \( h(x) \) for each \( x \) are:
- For \( x = -3 \), \( h(-3) = -7 \)
- For \( x = -1 \), \( h(-1) = 1 \)
- For \( x = 0 \), \( h(0) = 5 \)
- For \( x = 2 \), \( h(2) = 13 \)
- For \( x = 3 \), \( h(3) = 17 \)
\[
\begin{array}{|c|c|}
\hline
x & h(x) \\
\hline
-3 & -7 \\
-1 & 1 \\
0 & 5 \\
2 & 13 \\
3 & 17 \\
\hline
\end{array}
\]
So the values of \( h(x) \) for each \( x \) are:
- For \( x = -3 \), \( h(-3) = -7 \)
- For \( x = -1 \), \( h(-1) = 1 \)
- For \( x = 0 \), \( h(0) = 5 \)
- For \( x = 2 \), \( h(2) = 13 \)
- For \( x = 3 \), \( h(3) = 17 \)