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This question has two parts. First, answer Part A. Then answer Part B.

Part A

Pea seed pods can be either green (GG) or yellow (gg). When crossed using a Punnett Square, what is the percentage chance of GG x gg parents producing offspring that are heterozygous for pea color?

50%

100%

75%

0%

25%

Part B

Referencing the answer to the question above, what are the genotype and phenotype for the resultant offspring?

Gg (yellow)

Gg (green)

GG (green)

gg (yellow)

1 answer

Part A:

To determine the percentage chance of offspring that are heterozygous (Gg) from a cross between GG (homozygous green) and gg (homozygous yellow) pea plants, we can set up a Punnett Square.

  • Parent 1 (GG) can only contribute G alleles.
  • Parent 2 (gg) can only contribute g alleles.

The Punnett Square would look like this:

     G   |   G
----------------
 g |  Gg  |  Gg  
----------------
 g |  Gg  |  Gg

All offspring will be Gg, which means 100% of the offspring will be heterozygous for pea color.

Answer for Part A: 100%

Part B:

In the cross described, all offspring will have the genotype Gg, which is heterozygous.

To determine the phenotype, G is the dominant allele for green color, and g is the recessive allele for yellow color. Since G is dominant, any plant that has at least one G allele will exhibit the green phenotype.

Thus, the offspring will all be:

  • Genotype: Gg
  • Phenotype: Green

Answer for Part B: Gg (green)