64y^3-125
8x^3+125
Please help me I do not understand.
Must done today.
4 answers
Are both equations supposed to be set to zero???
they are factor complete or state that the polynomial is prime.
64y^3-125
8x^3+125
so help me please.
64y^3-125
8x^3+125
so help me please.
We can factor both the difference and the sum of 2 cubes
A^3 - B^3 = (A-B)(A^2 + AB + B^2)
A^3 + B^3 = (A+B)(A^2 - AB + B^2)
64y^3 - 125
= (4y-5)(16y^2 + 20y + 25)
you try the second one
A^3 - B^3 = (A-B)(A^2 + AB + B^2)
A^3 + B^3 = (A+B)(A^2 - AB + B^2)
64y^3 - 125
= (4y-5)(16y^2 + 20y + 25)
you try the second one
8x^3+125=(4-5)(2x^2+20+25)
the problem is about factor complete, or state that the polynomial is prime.
could you check and see if I got it right.
the problem is about factor complete, or state that the polynomial is prime.
could you check and see if I got it right.