What is (a^2−11)+(3a^2−4a+6)?(1 point)

Answer 1

To simplify the expression $(a^2-11)+(3a^2-4a+6)$, you can first distribute and then combine like terms.

1. Start with the original expression: $$(a^2-11)+(3a^2-4a+6)$$

2. Remove the parentheses: $$a^2-11+3a^2-4a+6$$

3. Combine like terms:

   • Combine the $a^2$ terms: $a^2+3a^2=4a^2$
   • Combine the $a$ terms: $-4a$
   • Combine the constants: $-11+6=-5$

Putting it all together, we get: $$4a^2-4a-5$$

So, the simplified expression is: $$\boxed{{\displaystyle 4a^2-4a-5}}$$