the graph of a function f(x) passes through the following points:

(0,-2),(1,0),(-1,-4)
which of the following could be f(x)?
a)f(x)=2x-2
b)f(x)=2x^2-2
c)f(x)=-2x-2
d)f(x)=2√x-2

1 answer

To determine which function \( f(x) \) passes through the points \((0, -2)\), \((1, 0)\), and \((-1, -4)\), we can evaluate each of the provided options at these specific \( x \) values.

a) \( f(x) = 2x - 2 \)

  • For \( x = 0 \): \[ f(0) = 2(0) - 2 = -2 \quad \text{(matches)} \]
  • For \( x = 1 \): \[ f(1) = 2(1) - 2 = 0 \quad \text{(matches)} \]
  • For \( x = -1 \): \[ f(-1) = 2(-1) - 2 = -2 - 2 = -4 \quad \text{(matches)} \]

This function matches all three points.

b) \( f(x) = 2x^2 - 2 \)

  • For \( x = 0 \): \[ f(0) = 2(0)^2 - 2 = -2 \quad \text{(matches)} \]
  • For \( x = 1 \): \[ f(1) = 2(1)^2 - 2 = 2 - 2 = 0 \quad \text{(matches)} \]
  • For \( x = -1 \): \[ f(-1) = 2(-1)^2 - 2 = 2 - 2 = 0 \quad \text{(does NOT match)} \]

This function does NOT match all three points.

c) \( f(x) = -2x - 2 \)

  • For \( x = 0 \): \[ f(0) = -2(0) - 2 = -2 \quad \text{(matches)} \]
  • For \( x = 1 \): \[ f(1) = -2(1) - 2 = -2 - 2 = -4 \quad \text{(does NOT match)} \]
  • For \( x = -1 \): \[ f(-1) = -2(-1) - 2 = 2 - 2 = 0 \quad \text{(does NOT match)} \]

This function does NOT match all three points.

d) \( f(x) = 2\sqrt{x} - 2 \)

  • For \( x = 0 \): \[ f(0) = 2\sqrt{0} - 2 = -2 \quad \text{(matches)} \]
  • For \( x = 1 \): \[ f(1) = 2\sqrt{1} - 2 = 2 - 2 = 0 \quad \text{(matches)} \]
  • For \( x = -1 \): \[ f(-1) \quad \text{(undefined as you can't take the square root of a negative number)} \]

This function does NOT match all three points.

Conclusion

The only function that matches all three points is:

a) \( f(x) = 2x - 2 \)

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