Fill in the blank question.

Jim has a yard sign measuring 45 centimeters by 60 centimeters for his mayoral campaign. He wants to use the same image for a sticker. Jim reduces the image by a scale factor of 15, and to print the sticker, he reduces the second image by a scale factor of 13.

What are the dimensions of the sticker? Write the smaller dimension first and the larger dimension second.

5 answers

To find the dimensions of the sticker, we first need to reduce the original dimensions of the yard sign (45 cm by 60 cm) by a scale factor of 15, and then further reduce the resulting dimensions by a scale factor of 13.

  1. Reduce by a scale factor of 15:

    • Smaller dimension: \( 45 , \text{cm} \div 15 = 3 , \text{cm} \)
    • Larger dimension: \( 60 , \text{cm} \div 15 = 4 , \text{cm} \)

    After this step, the dimensions are 3 cm and 4 cm.

  2. Reduce by a scale factor of 13:

    • Smaller dimension: \( 3 , \text{cm} \div 13 = \frac{3}{13} , \text{cm} \)
    • Larger dimension: \( 4 , \text{cm} \div 13 = \frac{4}{13} , \text{cm} \)

Thus, the final dimensions of the sticker are \( \frac{3}{13} , \text{cm} \) (smaller dimension) and \( \frac{4}{13} , \text{cm} \) (larger dimension).

Therefore, the dimensions of the sticker are:

\(\frac{3}{13} , \text{cm}, \frac{4}{13} , \text{cm}\).

Are the reduced images similar to the original? Write yes or no.

Yes.

What are the dimensions of the sticker?

Let's recalculate the dimensions of the sticker based on the original dimensions of the yard sign (45 cm by 60 cm) and the provided scale factors.

  1. Reduce by a scale factor of 15:

    • Smaller dimension: \( 45 , \text{cm} \div 15 = 3 , \text{cm} \)
    • Larger dimension: \( 60 , \text{cm} \div 15 = 4 , \text{cm} \)

    Now, the dimensions are 3 cm and 4 cm.

  2. Reduce this image by a scale factor of 13:

    • Smaller dimension: \( 3 , \text{cm} \div 13 = \frac{3}{13} , \text{cm} \)
    • Larger dimension: \( 4 , \text{cm} \div 13 = \frac{4}{13} , \text{cm} \)

Thus, the dimensions of the sticker are:

\(\frac{3}{13} , \text{cm}, \frac{4}{13} , \text{cm}\).

Please note that if the first reduction was indeed the intended operation, the answer holds true. However, if the original dimensions were to first reduce the height 45 cm by a factor of 15 and then the width of 60 cm also by a factor of 15, it would lead to different dimensions. Let me know if you would like that calculation instead!

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