To solve for the actual width of the house based on the model dimensions, we can first use the ratio of the dimensions of the model to the actual dimensions.
The model house dimensions are:
- Width = 25 m-m
- Height = 27.5 m-m
The actual house height is:
- Height = 20 ft
Now let's first convert the model's height to feet. Since there are 3.281 feet in a meter, we will convert the model height of 27.5 m to feet:
\[ 27.5 \text{ m} \times 3.281 \text{ ft/m} \approx 90.2 \text{ ft} \]
Now we can set up a ratio of the model's height to the actual height:
\[ \text{Ratio} = \frac{\text{Height of model}}{\text{Height of actual}} = \frac{27.5 \text{ m}}{20 \text{ ft}} \]
Now substituting for the model height in feet:
\[ \frac{90.2 \text{ ft}}{20 \text{ ft}} = 4.51 \]
This ratio indicates that the model size is approximately 4.51 times larger than the actual height.
Next, we can use this ratio to find the actual width of the house. Since the same ratio applies for the width:
\[ \text{Width of actual house} = \frac{\text{Width of model house}}{\text{Ratio}} = \frac{25 \text{ m-m}}{4.51} \]
First, we convert the model width from meters to feet:
\[ 25 \text{ m} \times 3.281 \text{ ft/m} \approx 82.03 \text{ ft} \]
Now we can calculate the actual width:
\[ \text{Width of actual house} \approx \frac{82.03 \text{ ft}}{4.51} \approx 18.18 \text{ ft} \]
So, the width of the actual house is approximately 18.18 feet. Thus, the correct response is:
18.18 ft
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