Question
Solve the square root equation 2x+9−−−−−√=x+5
2
𝑥
+
9
=
𝑥
+
5
.(1 point)
The solution to the square root equation is x
2
𝑥
+
9
=
𝑥
+
5
.(1 point)
The solution to the square root equation is x
Answers
GPT-4o mini
To solve the equation \( \sqrt{2x + 9} = x + 5 \), we will first square both sides to eliminate the square root:
\[
(\sqrt{2x + 9})^2 = (x + 5)^2
\]
This simplifies to:
\[
2x + 9 = (x + 5)(x + 5)
\]
Expanding the right side:
\[
2x + 9 = x^2 + 10x + 25
\]
Now, rearranging the equation to set it to zero:
\[
0 = x^2 + 10x + 25 - 2x - 9
\]
Combine like terms:
\[
0 = x^2 + 8x + 16
\]
Now, we can factor the quadratic:
\[
0 = (x + 4)(x + 4) = (x + 4)^2
\]
Setting the factor equal to zero gives:
\[
x + 4 = 0 \quad \Rightarrow \quad x = -4
\]
Now we need to check whether this solution satisfies the original equation:
Substituting \( x = -4 \) back into the original equation:
\[
\sqrt{2(-4) + 9} = -4 + 5
\]
Calculating the left side:
\[
\sqrt{-8 + 9} = \sqrt{1} = 1
\]
Calculating the right side:
\[
-4 + 5 = 1
\]
Since both sides are equal, \( x = -4 \) is indeed a valid solution.
Thus, the solution to the square root equation is:
\[
\boxed{-4}
\]
\[
(\sqrt{2x + 9})^2 = (x + 5)^2
\]
This simplifies to:
\[
2x + 9 = (x + 5)(x + 5)
\]
Expanding the right side:
\[
2x + 9 = x^2 + 10x + 25
\]
Now, rearranging the equation to set it to zero:
\[
0 = x^2 + 10x + 25 - 2x - 9
\]
Combine like terms:
\[
0 = x^2 + 8x + 16
\]
Now, we can factor the quadratic:
\[
0 = (x + 4)(x + 4) = (x + 4)^2
\]
Setting the factor equal to zero gives:
\[
x + 4 = 0 \quad \Rightarrow \quad x = -4
\]
Now we need to check whether this solution satisfies the original equation:
Substituting \( x = -4 \) back into the original equation:
\[
\sqrt{2(-4) + 9} = -4 + 5
\]
Calculating the left side:
\[
\sqrt{-8 + 9} = \sqrt{1} = 1
\]
Calculating the right side:
\[
-4 + 5 = 1
\]
Since both sides are equal, \( x = -4 \) is indeed a valid solution.
Thus, the solution to the square root equation is:
\[
\boxed{-4}
\]