Identify the vertex of y=4(x−25)^2−61

Question

.(1 point)
Responses

(25,−61)
left parenthesis 25 comma negative 61 right parenthesis

(4,−25)
left parenthesis 4 comma negative 25 right parenthesis

(−25,−61)
left parenthesis negative 25 comma negative 61 right parenthesis

(−100,−61)

Answer 1

To find the vertex of the quadratic function \( y = 4(x - 25)^2 - 61 \), we can use the vertex form of a parabola, which is given by \( y = a(x - h)^2 + k \). In this form, the vertex \((h, k)\) can be directly identified.

Here, \( a = 4 \), \( h = 25 \), and \( k = -61 \).

So, the vertex is:

\[ (25, -61) \]

Therefore, the correct response is:

(25,−61)