To solve the quadratic equation \( x^2 - 6x - 20 = 20 \) by completing the square, follow these steps:
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First, move all terms to one side of the equation: \[ x^2 - 6x - 20 - 20 = 0 \] This simplifies to: \[ x^2 - 6x - 40 = 0 \]
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Next, we isolate the \( x^2 \) and \( x \) terms: \[ x^2 - 6x = 40 \]
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Now, we will complete the square. Take half of the coefficient of \( x \) (which is \(-6\)), square it, and add it to both sides. Half of \(-6\) is \(-3\), and squaring it gives \(9\): \[ x^2 - 6x + 9 = 40 + 9 \] This simplifies to: \[ (x - 3)^2 = 49 \]
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Now solve for \( x \) by taking the square root of both sides: \[ x - 3 = \pm 7 \]
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This gives us two equations:
- \( x - 3 = 7 \) which leads to \( x = 10 \)
- \( x - 3 = -7 \) which leads to \( x = -4 \)
So, the solutions to the equation are: \[ x = 10 \quad \text{and} \quad x = -4 \]
The correct response is: x = 10, x = -4.