To find the high or low point (vertex) of the parabola defined by the quadratic equation \(y = -6x^2 + 3x + 8\), we can use the formula for the x-coordinate of the vertex of a parabola given by \(x = -\frac{b}{2a}\), where \(a\) and \(b\) are the coefficients from the equation \(y = ax^2 + bx + c\).
In this case:
- \(a = -6\)
- \(b = 3\)
- \(c = 8\)
Calculating the x-coordinate of the vertex: \[ x = -\frac{3}{2 \cdot -6} = -\frac{3}{-12} = \frac{1}{4} = 0.25 \]
Next, we substitute \(x = 0.25\) back into the equation to find the y-coordinate of the vertex: \[ y = -6(0.25)^2 + 3(0.25) + 8 \] Calculating: \[ = -6(0.0625) + 0.75 + 8 = -0.375 + 0.75 + 8 = 0.375 + 8 = 8.375 \]
Thus, the vertex of the parabola is \((0.25, 8.375)\).
Since the leading coefficient \(a\) is negative (-6), the parabola opens downward, indicating that the vertex represents a high point.
So the correct response is: \[ (0.25, 8.375) \text{ is the high point on the parabola.} \]