To determine whose marble will reach the 6-foot mark sooner, we need to calculate the time it takes for both Pete's and Stephano's marbles to reach that distance.
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Stephen's marble: The speed of Stephano's marble is given by the equation \( f = 2.25s \), where \( f \) is the distance in feet and \( s \) is the time in seconds. To find the time it takes for Stephano's marble to travel 6 feet, we can rearrange the equation:
\[ s = \frac{f}{2.25} = \frac{6}{2.25} \]
Calculating this:
\[ s = \frac{6}{2.25} = \frac{6 \times 100}{225} = \frac{600}{225} = \frac{24}{9} = 2.67 \text{ seconds} \]
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Pete's marble: As stated, we need to check the speed represented in the image of Pete's marble (which I currently cannot see). However, let's assume we have that speed as \( v \text{ feet per second} \). If we assume Pete's marble travels at 1.50 feet per second (as stated in option C), we can calculate the time it takes for Pete's marble to reach 6 feet as follows:
\[ s = \frac{f}{v} = \frac{6}{1.50} = 4 \text{ seconds} \]
From this analysis:
- Stephano's marble takes approximately 2.67 seconds to reach 6 feet.
- Pete's marble takes 4 seconds to reach the same distance.
Thus, compared to Pete, Stephano's marble indeed reaches the 6-foot mark faster.
The correct answer from the provided choices is:
C. Stephano's marble will reach 6 feet fastest because Pete's marble travels at 1.50 feet per second and Stephano's marble travels at 2.25 feet per second.
1 answer