How many real solutions does the following quadratic equation have?

4x^2+x+3=0


(1 point)
Responses

one real solution
one real solution

three real solutions
three real solutions

two real solutions
two real solutions

no real solutions

1 answer

To determine the number of real solutions of the quadratic equation \(4x^2 + x + 3 = 0\), we can analyze the discriminant of the quadratic equation, which is given by the formula:

\[ D = b^2 - 4ac \]

In this case, the coefficients are:

  • \(a = 4\)
  • \(b = 1\)
  • \(c = 3\)

Now, we can calculate the discriminant:

\[ D = (1)^2 - 4(4)(3) = 1 - 48 = 1 - 48 = -47 \]

Since \(D < 0\), this means the quadratic equation has no real solutions.

Thus, the correct response is:

no real solutions