To solve the quadratic equation \(2x^2 - 5x - 6 = 0\), we can first rearrange it to the standard form:
\[ 2x^2 - 5x - 6 = 0 \]
Next, we will use the quadratic formula, which is
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
For our equation, the coefficients are:
- \(a = 2\)
- \(b = -5\)
- \(c = -6\)
Now we can calculate \(b^2 - 4ac\):
\[ b^2 - 4ac = (-5)^2 - 4(2)(-6) = 25 + 48 = 73 \]
Now substituting back into the quadratic formula:
\[ x = \frac{-(-5) \pm \sqrt{73}}{2(2)} = \frac{5 \pm \sqrt{73}}{4} \]
Now we will calculate the two possible values for \(x\):
- Using the positive root:
\[ x_1 = \frac{5 + \sqrt{73}}{4} \approx \frac{5 + 8.544}{4} \approx \frac{13.544}{4} \approx 3.386 \]
- Using the negative root:
\[ x_2 = \frac{5 - \sqrt{73}}{4} \approx \frac{5 - 8.544}{4} \approx \frac{-3.544}{4} \approx -0.886 \]
When rounded to the nearest hundredth, \(x_2 \approx -0.89\).
So, the solution rounded to the nearest hundredth is:
\[ \boxed{x = -0.89} \]
Thus, the correct response from the given options is:
x = −0.89.