Question
How to calculate the quantity of heat gained or lost in the following change:
3.50 mol of water freezes at 0 degrees C?
Would it be 6.01kJ/ 3.50 mol ?
3.50 mol of water freezes at 0 degrees C?
Would it be 6.01kJ/ 3.50 mol ?
Answers
Not quite.
6.01 kJ/mol x 3.50 mol = ??
Note that your arrangement gives kJ/mol; my arrangement the mol cancel to give kJ as the answer and that is the quantity of heat.
6.01 kJ/mol x 3.50 mol = ??
Note that your arrangement gives kJ/mol; my arrangement the mol cancel to give kJ as the answer and that is the quantity of heat.
21kj lost
-21.0 KJ (21.0 KJ lost)
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